Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (2024)

Engage NY Eureka Math 5th Grade Module 6 Lesson 16 Answer Key

Eureka Math Grade 5 Module 6 Lesson 16 Problem Set Answer Key

Question 1.
Use the coordinate plane below to complete the following tasks.
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (1)
a. Draw \(\overline{A B}\).
b. Plot point C (0, 8).
c. Draw \(\overline{A C}\).
d. Explain how you know ∠CAB is a right angle without measuring it.
e. Sean drew the picture below to find a segment perpendicular to (AB) ̅. Explain why Sean is correct.
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (2)
Answer:
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (3)
d.
Explanation :
∠CAB is a right angle because I can Draw a triangle that has \(\overline{A B}\) has its long side. The length is 5 units and the Height is 2 units . When I slide the triangle to the left and rotated, I know 2 acute angles will form a 90 degrees or right angle .
e.
Sean is correct because I notice that he slid and rotated the triangle and the 2 acute angles form the right angle .

Question 2.
Use the coordinate plane below to complete the following tasks.
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (4)
a. Draw \(\overline{Q T}\).
b. Plot point R (2, 6\(\frac{1}{2}\)).
c. Draw \(\overline{Q R}\).
d. Explain how you know ∠RQT is a right angle without measuring it.
e. Compare the coordinates of points Q and T. What is the difference of the x-coordinates? The y-coordinates?
f. Compare the coordinates of points Q and R. What is the difference of the x-coordinates? The y-coordinates?
g. What is the relationship of the differences you found in parts (e) and (f) to the triangles of which these two segments are a part?
Answer:
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (5)
d.
Explanation :
Triangles are drawn when I slid and rotated the triangle. I know that 2 acute angles will form 90 degrees. If they form 90 degrees the angle between them , ∠RQT will be 90 degrees Since the 3 angles form a straight line .
e. The coordinates of points Q and T are ( 3\(\frac{1}{2}\) , 4 ) and (6, 5\(\frac{1}{2}\)) Respectively .
The differences of x- coordinate = 6 – 3\(\frac{1}{2}\)= 2\(\frac{1}{2}\) .
The difference of y-coordinate = 5\(\frac{1}{2}\) – 4 = 1\(\frac{1}{2}\).
f. The coordinates of points Q and R are ( 3\(\frac{1}{2}\) , 4 ) and (2, 6\(\frac{1}{2}\)) Respectively .
The differences of x- coordinate = 3\(\frac{1}{2}\) – 2 = 1\(\frac{1}{2}\) .
The difference of y-coordinate = 6\(\frac{1}{2}\) – 4 = 2\(\frac{1}{2}\).
g. The differences in the X-coordinate of the points Q and T is same as the differences in the Y-coordinate of the points Q and R .
The differences in the Y-coordinate of the points Q and T is same as the differences in the X-coordinate of the points Q and R. Just the Numbers flipped.

Question 3.
\(\overline{E F}\) contains the following points. E: (4, 1) F: (8, 7)
Give the coordinates of a pair of points G and H, such that \(\overline{E F}\) ⊥ \(\overline{G H}\).
G: (_____, _____) H: (_____, _____)
Answer:
As the above rule is applied of Question -2-g and the Coordinate of Points are written .
G: (1, 8) H: ( 7, 4)

Eureka Math Grade 5 Module 6 Lesson 16 Exit Ticket Answer Key

Use the coordinate plane below to complete the following tasks.
a. Draw \(\overline{U V}\).
b. Plot point W (4\(\frac{1}{2}\),6).
c. Draw \(\overline{V W}\).
d. Explain how you know that ∠UVW is a right angle without measuring it.
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (6)
Answer:
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (7)
d.
Explanation :
Triangles are drawn when I slid and rotated the triangle. I know that 2 acute angles will form 90 degrees. If they form 90 degrees the angle between them , ∠UVW will be 90 degrees Since the 3 angles form a straight line .

Eureka Math Grade 5 Module 6 Lesson 16 Homework Answer Key

Question 1.
Use the coordinate plane below to complete the following tasks.
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (8)
a. Draw \(\overline{P Q}\).
b. Plot point R (3, 8).
c. Draw \(\overline{P R}\).
d. Explain how you know ∠RPQ is a right angle without measuring it.
e. Compare the coordinates of points P and Q. What is the difference of the x-coordinates? The y-coordinates?
f. Compare the coordinates of points P and R. What is the difference of the x-coordinates? The y-coordinates?
g. What is the relationship of the differences you found in parts (e) and (f) to the triangles of which these two segments are a part?
Answer:
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (9)
d. Explanation :
Triangles are drawn when I slid and rotated the triangle. I know that 2 acute angles will form 90 degrees. If they form 90 degrees the angle between them , ∠RPQ will be 90 degrees Since the 3 angles form a straight line .
e. The coordinates of points P and Q are ( 2, 4 ) and (6, 3) Respectively .
The differences of x- coordinate = 6 – 2= 4 .
The difference of y-coordinate = 4- 3 = 1.
f. The coordinates of points P and R are ( 2, 4 ) and ( 3, 8 ) Respectively .
The differences of x- coordinate = 3 – 2 = 1
The difference of y-coordinate = 8 – 4 = 4
g. The differences in the X-coordinate of the points P and Q is same as the differences in the Y-coordinate of the points P and R .
The differences in the Y-coordinate of the points P and Q is same as the differences in the X-coordinate of the points P and R . Just the Numbers flipped.

Question 2.
Use the coordinate plane below to complete the following tasks.
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (10)
a. Draw \(\overline{C B}\).
b. Plot point D(\(\frac{1}{2}\), 5\(\frac{1}{2}\)).
c. Draw \(\overline{C D}\).
d. Explain how you know ∠DCB is a right angle without measuring it.
e. Compare the coordinates of points C and B. What is the difference of the x-coordinates? The y-coordinates?
f. Compare the coordinates of points C and D. What is the difference of the x-coordinates? The y-coordinates?
g. What is the relationship of the differences you found in parts (e) and (f) to the triangles of which these two segments are a part?
Answer:
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (11)
d. Explanation :
Triangles are drawn when I slid and rotated the triangle. I know that 2 acute angles will form 90 degrees. If they form 90 degrees the angle between them , ∠DCB will be 90 degrees Since the 3 angles form a straight line .
e. The coordinates of pointsC and B. are (1\(\frac{3}{4}\), 4 ) and (3\(\frac{1}{4}\), 5) Respectively .
The differences of x- coordinate = 3\(\frac{1}{4}\) – 1\(\frac{3}{4}\) = \(\frac{13}{4}\) –\(\frac{7}{4}\) = 1\(\frac{6}{4}\)=\(\frac{2}{3}\)
The difference of y-coordinate = 5 – 4 =1
f. The coordinates of points C and D are (1\(\frac{3}{4}\), 4 ) and (\(\frac{1}{2}\), 5\(\frac{1}{2}\)) Respectively .
The differences of x- coordinate = 1\(\frac{3}{4}\) – \(\frac{1}{2}\) = \(\frac{7}{4}\)– \(\frac{2}{4}\)= \(\frac{5}{4}\)= 1\(\frac{1}{4}\)
The difference of y-coordinate =5\(\frac{1}{2}\) – 4 = 1\(\frac{1}{2}\)
g. All the differences are different .No Relationship is formed .

Question 3.
\(\overline{S T}\) contains the following points. S: (2, 3) T: (9, 6)
Give the coordinates of a pair of points, U and V, such that \(\overline{S T}\) ⊥ \(\overline{S T}\).
U: (_____, _____) V: (_____, _____)
Answer:
Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (12)
the coordinates of a pair of points, U and V, such that \(\overline{S T}\) ⊥ \(\overline{S T}\).
U: (, ) V: (_____, _____)
The coordinates of points S and T are(2, 3) and (9, 6) Respectively .
The differences of x- coordinate = 9 – 2= 7 .
The difference of y-coordinate = 6- 3 = 3.

The coordinates of points T and (6, 13) are (9, 6) and (6, 13)
The differences of x- coordinate = 9 – 6 = 3
The difference of y-coordinate = 13 – 6 = 7

The differences in the X-coordinate of the points S and T is same as the differences in the Y-coordinate of the points T and (6, 13) .
The differences in the Y-coordinate of the points S and T is same as the differences in the X-coordinate of the points T and (6, 13) . Just the Numbers flipped.
U: (3, 9) V: (6, 2)

Eureka Math Grade 5 Module 6 Lesson 16 Answer Key (2024)

FAQs

What grade does Eureka math go up to? ›

Eureka Math® is a holistic Prekindergarten through Grade 12 curriculum that carefully sequences mathematical progressions in expertly crafted modules, making math a joy to teach and learn. We provide in-depth professional development, learning materials, and a community of support.

What are the four core components of a Eureka Math TEKS lesson? ›

A typical Eureka lesson is comprised of four critical components: fluency practice, concept development (including a problem set), application problem, and student debrief (including the Exit Ticket).

What is the purpose of the concept development in Eureka math? ›

The concept development is generally comprised of carefully sequenced problems centered within a specific topic to begin developing mastery via gradual increases in complexity.

What is the hardest math in 5th grade? ›

Some of the hardest math problems for fifth graders involve multiplying: multiplying using square models, multiplying fractions and whole numbers using expanded form, and multiplying fractions using number lines.

What's the hardest math class? ›

1. Real Analysis: This course is sometimes referred to as the most difficult undergraduate math course because it delves deep into the theoretical foundations of calculus. It relies heavily on rigorous proofs and demands a high level of abstract thinking.

Is Eureka Math scripted? ›

Eureka Math is scripted for the teacher and anticipates student responses, which is very useful for studying in advance. This makes each module easy to follow and easy to understand what is expected.

Is Eureka math common core math? ›

Eureka Math is a Common Core math. Eureka Math's framework is entirely built on the Common Core Learning Standards and Progressions for the Common Core State Standards in Mathematics.

How many states use Eureka math? ›

We wrote EngageNY Math, and over time we developed that program into Eureka Math. The original OER curriculum is available on the EngageNY and Great Minds sites for free, and it has been downloaded over 13 million times by users in all 50 states, making Eureka Math the most widely used K–5 math program in the country.

Who created Eureka math? ›

LYNNE MUNSON

At the urging of educators seeking knowledge-building resources, Lynne and her team moved into curriculum development with Common Core curriculum maps in English language arts and then with EngageNY, which later became Eureka Math®.

Who is the father of math Eureka? ›

Sometimes called the father of mathematics and mathematical physics, Archimedes had a wide influence on mathematics and science.

What are the goals of Eureka Math? ›

Eureka Math exhibits unparalleled rigor throughout the grades. Students develop conceptual understanding and practice procedural skills and fluency. They also have opportunities to connect their learning with real-life application problems.

What is the highest level of math in 9th grade? ›

9th grade math usually focuses on Algebra I, but can include other advanced mathematics such as Geometry, Algebra II, Pre-Calculus or Trigonometry.

What is 8th grade advanced math? ›

Students on the advanced math track will take Algebra. This standards-based class covers the second half of Math 8 as well as high school-level Algebra I and is designed to prepare students for geometry in ninth grade. Placement is based on prior grades, teacher recommendations, and district benchmark testing scores.

What grade level does prodigy math go up to? ›

With 1,500+ curriculum-aligned math skills for 1st to 8th grade, Prodigy Math is so much more than a game. Prodigy Math is an engaging game-based learning platform that's dedicated to improving students' confidence and achievements in math.

What is the highest math class ever? ›

Math 55 is a two-semester freshman undergraduate mathematics course at Harvard University founded by Lynn Loomis and Shlomo Sternberg. The official titles of the course are Studies in Algebra and Group Theory (Math 55a) and Studies in Real and Complex Analysis (Math 55b).

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